A projectile is thrown upward. It reaches apogee at which point it is moving in a parabola.

It then falls back to earth, reaching its lowest point at perigee. Finally, it lands at the same height from which it was thrown (where x = 0).

The time taken for the projectile to reach apogee is given by t = 2π√12 h where h is the height of the thrower above the ground when the projectile is released.

The time taken for the projectile to fall back to earth (from apogee) is given by t = 2π√4 h where h is the height of the thrower above the ground when the projectile is released.

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Last modified: October 8, 2022